[dhwriter]

Originally Posted by ilovemykidsmore

I was confused about the 2 BOGO as well, but as I read the other posts and thought more about it, I think I have it figured out. You have product X and coupon Z. Put on the counter 1X 2X 3X. Use coupon 1Z, so pay for 1X and get 2X free. Coupon 2Z is for 2X so pay for 2X (but not really cause 1Z got it free) and get 3X free. Follow? Makes perfect sense to me, but could be because it's after 1 am. This is actually better than walking out the store with 4.

Yes, I think you're right. You pay for the first item, and your first BOGO coupon is applied against it. At that point, you have 2 items. Your second BOGO coupon is applied against the free item that you "bought" with the first BOGO coupon. Thus, you're paying for 1 and getting 3. That is cheaper than buying 2 and getting 2 free. For example, if the item costs $4, in the first scenario you pay $4 for 3, or $1.33 each. In the second scenario, you pay $8 for 4, or $2.00 each.

My interpretation of the memo is that this scenario (2 BOGO coupons, 3 items total) is for when there is NOT a BOGO sale going on. When there is a BOGO sale, use one coupon for each pair of items and they're both free.